Face centred cubic crystal lattice of copper has density of 8.966 g.cm^{-3}. Calculate the volume of the unit cell. Given molar mass of copper is 63.5 g mol^{-1} and Avogadro number N_{A }is 6.022 x 10^{23} mol^{-1}

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#### Solution

Data: d=8.966 g cm^{-1}

M.M. of copper = 63.5 gmol^{–1}

N_{A}=6.022XX10^{23}

Solution : `d=(ZxxM)/(VxxN_A)`

Z=4(∵ Fcc)

`V=(ZxxM)/(d xx N_A)`

`=(4xx63.5)/(8.966xx6.023xx10^23)`

V=4.704x10^{-23} cm^{3} |

Concept: Number of Atoms in a Unit Cell

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